8x+4-2(x+8)=-3(2x-1)+6

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Solution for 8x+4-2(x+8)=-3(2x-1)+6 equation: 



8x+4-2(x+8)=-3(2x-1)+6

We move all terms to the left:

8x+4-2(x+8)-(-3(2x-1)+6)=0

We multiply parentheses

8x-2x-(-3(2x-1)+6)-16+4=0



We calculate terms in parentheses: -(-3(2x-1)+6), so:

-3(2x-1)+6

We multiply parentheses

-6x+3+6

We add all the numbers together, and all the variables

-6x+9

Back to the equation:

-(-6x+9)



We add all the numbers together, and all the variables

6x-(-6x+9)-12=0

We get rid of parentheses

6x+6x-9-12=0

We add all the numbers together, and all the variables

12x-21=0

We move all terms containing x to the left, all other terms to the right

12x=21

x=21/12

x=1+3/4

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