8x+4(4x+3)=(6x+)-4

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Solution for 8x+4(4x+3)=(6x+)-4 equation: 



8x+4(4x+3)=(6x+)-4

We move all terms to the left:

8x+4(4x+3)-((6x+)-4)=0

We add all the numbers together, and all the variables

8x+4(4x+3)-((+6x)-4)=0

We multiply parentheses

8x+16x-((+6x)-4)+12=0



We calculate terms in parentheses: -((+6x)-4), so:

(+6x)-4

We get rid of parentheses

6x-4

Back to the equation:

-(6x-4)



We add all the numbers together, and all the variables

24x-(6x-4)+12=0

We get rid of parentheses

24x-6x+4+12=0

We add all the numbers together, and all the variables

18x+16=0

We move all terms containing x to the left, all other terms to the right

18x=-16

x=-16/18

x=-8/9

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