35+4n=2(5n-1)+7

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Solution for 35+4n=2(5n-1)+7 equation: 



35+4n=2(5n-1)+7

We move all terms to the left:

35+4n-(2(5n-1)+7)=0



We calculate terms in parentheses: -(2(5n-1)+7), so:

2(5n-1)+7

We multiply parentheses

10n-2+7

We add all the numbers together, and all the variables

10n+5

Back to the equation:

-(10n+5)



We get rid of parentheses

4n-10n-5+35=0

We add all the numbers together, and all the variables

-6n+30=0

We move all terms containing n to the left, all other terms to the right

-6n=-30

n=-30/-6

n=+5

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