8x+3-5x=2(3x-2)+28

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Solution for 8x+3-5x=2(3x-2)+28 equation: 



8x+3-5x=2(3x-2)+28

We move all terms to the left:

8x+3-5x-(2(3x-2)+28)=0

We add all the numbers together, and all the variables

3x-(2(3x-2)+28)+3=0



We calculate terms in parentheses: -(2(3x-2)+28), so:

2(3x-2)+28

We multiply parentheses

6x-4+28

We add all the numbers together, and all the variables

6x+24

Back to the equation:

-(6x+24)



We get rid of parentheses

3x-6x-24+3=0

We add all the numbers together, and all the variables

-3x-21=0

We move all terms containing x to the left, all other terms to the right

-3x=21

x=21/-3

x=-7

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