2/3(9z-21)=-2z+10

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Solution for 2/3(9z-21)=-2z+10 equation: 



2/3(9z-21)=-2z+10

We move all terms to the left:

2/3(9z-21)-(-2z+10)=0



Domain of the equation: 3(9z-21)!=0

z∈R



We get rid of parentheses

2/3(9z-21)+2z-10=0

We multiply all the terms by the denominator


2z*3(9z-21)-10*3(9z-21)+2=0

Wy multiply elements

6z^2(9-30z(9+2=0

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