8x+2(x+5)=2(x-1)

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Solution for 8x+2(x+5)=2(x-1) equation: 



8x+2(x+5)=2(x-1)

We move all terms to the left:

8x+2(x+5)-(2(x-1))=0

We multiply parentheses

8x+2x-(2(x-1))+10=0



We calculate terms in parentheses: -(2(x-1)), so:

2(x-1)

We multiply parentheses

2x-2

Back to the equation:

-(2x-2)



We add all the numbers together, and all the variables

10x-(2x-2)+10=0

We get rid of parentheses

10x-2x+2+10=0

We add all the numbers together, and all the variables

8x+12=0

We move all terms containing x to the left, all other terms to the right

8x=-12

x=-12/8

x=-1+1/2

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