1-8(10x-3)=1-80x+24

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Solution for 1-8(10x-3)=1-80x+24 equation: 



1-8(10x-3)=1-80x+24

We move all terms to the left:

1-8(10x-3)-(1-80x+24)=0

We add all the numbers together, and all the variables

-8(10x-3)-(-80x+25)+1=0

We multiply parentheses

-80x-(-80x+25)+24+1=0

We get rid of parentheses

-80x+80x-25+24+1=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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