8x+2(4x-4)=(6x+4)

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Solution for 8x+2(4x-4)=(6x+4) equation: 



8x+2(4x-4)=(6x+4)

We move all terms to the left:

8x+2(4x-4)-((6x+4))=0

We multiply parentheses

8x+8x-((6x+4))-8=0



We calculate terms in parentheses: -((6x+4)), so:

(6x+4)

We get rid of parentheses

6x+4

Back to the equation:

-(6x+4)



We add all the numbers together, and all the variables

16x-(6x+4)-8=0

We get rid of parentheses

16x-6x-4-8=0

We add all the numbers together, and all the variables

10x-12=0

We move all terms containing x to the left, all other terms to the right

10x=12

x=12/10

x=1+1/5

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