(3x-3)+(3x-3)=(4x-14)

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Solution for (3x-3)+(3x-3)=(4x-14) equation: 



(3x-3)+(3x-3)=(4x-14)

We move all terms to the left:

(3x-3)+(3x-3)-((4x-14))=0

We get rid of parentheses

3x+3x-((4x-14))-3-3=0



We calculate terms in parentheses: -((4x-14)), so:

(4x-14)

We get rid of parentheses

4x-14

Back to the equation:

-(4x-14)



We add all the numbers together, and all the variables

6x-(4x-14)-6=0

We get rid of parentheses

6x-4x+14-6=0

We add all the numbers together, and all the variables

2x+8=0

We move all terms containing x to the left, all other terms to the right

2x=-8

x=-8/2

x=-4

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