8x+-3(x+-4)=3(x+-4)+6

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Solution for 8x+-3(x+-4)=3(x+-4)+6 equation: 



8x+-3(x+-4)=3(x+-4)+6

We move all terms to the left:

8x+-3(x+-4)-(3(x+-4)+6)=0

We add all the numbers together, and all the variables

8x-3(x-4)-(3(x-4)+6)+=0

We add all the numbers together, and all the variables

8x-3(x-4)-(3(x-4)+6)=0

We multiply parentheses

8x-3x-(3(x-4)+6)+12=0



We calculate terms in parentheses: -(3(x-4)+6), so:

3(x-4)+6

We multiply parentheses

3x-12+6

We add all the numbers together, and all the variables

3x-6

Back to the equation:

-(3x-6)



We add all the numbers together, and all the variables

5x-(3x-6)+12=0

We get rid of parentheses

5x-3x+6+12=0

We add all the numbers together, and all the variables

2x+18=0

We move all terms containing x to the left, all other terms to the right

2x=-18

x=-18/2

x=-9

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