(f-32)5/9f=50

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Solution for (f-32)5/9f=50 equation: 



(f-32)5/9f=50

We move all terms to the left:

(f-32)5/9f-(50)=0



Domain of the equation: 9f!=0

f!=0/9

f!=0

f∈R



We multiply all the terms by the denominator


(f-32)5-50*9f=0

We multiply parentheses

5f-50*9f-160=0

Wy multiply elements

5f-450f-160=0

We add all the numbers together, and all the variables

-445f-160=0

We move all terms containing f to the left, all other terms to the right

-445f=160

f=160/-445

f=-32/89

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