8x(2x-10)+4=32

Solution for 8x(2x-10)+4=32 equation:

8x(2x-10)+4=32

We move all terms to the left:

8x(2x-10)+4-(32)=0

We add all the numbers together, and all the variables

8x(2x-10)-28=0

We multiply parentheses

16x^2-80x-28=0

a = 16; b = -80; c = -28;
Δ = b2-4ac
Δ = -802-4·16·(-28)
Δ = 8192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8192}=\sqrt{4096*2}=\sqrt{4096}*\sqrt{2}=64\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-64\sqrt{2}}{2*16}=\frac{80-64\sqrt{2}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+64\sqrt{2}}{2*16}=\frac{80+64\sqrt{2}}{32}
$