3(4-x)+6=4x+12-x

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Solution for 3(4-x)+6=4x+12-x equation: 



3(4-x)+6=4x+12-x

We move all terms to the left:

3(4-x)+6-(4x+12-x)=0

We add all the numbers together, and all the variables

3(-1x+4)-(3x+12)+6=0

We multiply parentheses

-3x-(3x+12)+12+6=0

We get rid of parentheses

-3x-3x-12+12+6=0

We add all the numbers together, and all the variables

-6x+6=0

We move all terms containing x to the left, all other terms to the right

-6x=-6

x=-6/-6

x=1

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