If it's not what You are looking for type in the equation solver your own equation and let us solve it.
8x(2x+1)=0.
We multiply parentheses
16x^2+8x=0
a = 16; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·16·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*16}=\frac{-16}{32} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*16}=\frac{0}{32} =0 $
| 2(n−1)+7=5n−3(1+n)+8 | | -4=8n-2+6 | | -16r-2r+-3r=-17 | | 9v+4=2(v-5) | | 29-1e=1/3 | | 12(x-2)=60 | | 3(-2x-3)=-6x+9 | | 36−7 | | -14=m-4 | | x+5+25=90 | | 34m−2=14m+5 | | -4(f-19)=12 | | 4(d-5)-6=2(8-d)-d | | 2p+16=20 | | 2p+26=20 | | 6+5(x+1)=52 | | 3z=z−8 | | 4m-42-12m=36+5m | | 5n-3+6n=3-2n | | –42=4v–18 | | -7z=-6z-19 | | --2/9(-n+3/9)=2/9n-5/9 | | 2x-5x+12=27 | | 7n-21=3+3n | | 6r+20=-19+9r | | 8/x+9=73 | | 2x-5x+12=27 | | x^2-28x+195=0 | | 5k+-1=9+5k | | 4x+25-3x=2x+15 | | 6x^2-1=4x | | 8/x+9=74 |