4(d-5)-6=2(8-d)-d

Solution for 4(d-5)-6=2(8-d)-d equation:

4(d-5)-6=2(8-d)-d

We move all terms to the left:

4(d-5)-6-(2(8-d)-d)=0

We add all the numbers together, and all the variables

4(d-5)-(2(-1d+8)-d)-6=0

We multiply parentheses

4d-(2(-1d+8)-d)-20-6=0


We calculate terms in parentheses: -(2(-1d+8)-d), so:

2(-1d+8)-d

We add all the numbers together, and all the variables

-1d+2(-1d+8)

We multiply parentheses

-1d-2d+16

We add all the numbers together, and all the variables

-3d+16

Back to the equation:

-(-3d+16)


We add all the numbers together, and all the variables

4d-(-3d+16)-26=0

We get rid of parentheses

4d+3d-16-26=0

We add all the numbers together, and all the variables

7d-42=0

We move all terms containing d to the left, all other terms to the right

7d=42

d=42/7

d=6