8(2x-4)+10=58

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Solution for 8(2x-4)+10=58 equation: 



8(2x-4)+10=58

We move all terms to the left:

8(2x-4)+10-(58)=0

We add all the numbers together, and all the variables

8(2x-4)-48=0

We multiply parentheses

16x-32-48=0

We add all the numbers together, and all the variables

16x-80=0

We move all terms containing x to the left, all other terms to the right

16x=80

x=80/16

x=5

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