0.5(10x-12)=3x+22

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Solution for 0.5(10x-12)=3x+22 equation: 



0.5(10x-12)=3x+22

We move all terms to the left:

0.5(10x-12)-(3x+22)=0

We multiply parentheses

5x-(3x+22)-6=0

We get rid of parentheses

5x-3x-22-6=0

We add all the numbers together, and all the variables

2x-28=0

We move all terms containing x to the left, all other terms to the right

2x=28

x=28/2

x=14

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