8x(-6x-4)=3x-18

Solution for 8x(-6x-4)=3x-18 equation:

8x(-6x-4)=3x-18

We move all terms to the left:

8x(-6x-4)-(3x-18)=0

We multiply parentheses

-48x^2-32x-(3x-18)=0

We get rid of parentheses

-48x^2-32x-3x+18=0

We add all the numbers together, and all the variables

-48x^2-35x+18=0

a = -48; b = -35; c = +18;
Δ = b2-4ac
Δ = -352-4·(-48)·18
Δ = 4681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-\sqrt{4681}}{2*-48}=\frac{35-\sqrt{4681}}{-96}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+\sqrt{4681}}{2*-48}=\frac{35+\sqrt{4681}}{-96}
$