7(4x-2)+3(16-5x)-3(4x+1)=-1

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Solution for 7(4x-2)+3(16-5x)-3(4x+1)=-1 equation: 



7(4x-2)+3(16-5x)-3(4x+1)=-1

We move all terms to the left:

7(4x-2)+3(16-5x)-3(4x+1)-(-1)=0

We add all the numbers together, and all the variables

7(4x-2)+3(-5x+16)-3(4x+1)-(-1)=0

We add all the numbers together, and all the variables

7(4x-2)+3(-5x+16)-3(4x+1)+1=0

We multiply parentheses

28x-15x-12x-14+48-3+1=0

We add all the numbers together, and all the variables

x+32=0

We move all terms containing x to the left, all other terms to the right

x=-32

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