8v+5-2(-2v-3)=2(v-2)

Solution for 8v+5-2(-2v-3)=2(v-2) equation:

8v+5-2(-2v-3)=2(v-2)

We move all terms to the left:

8v+5-2(-2v-3)-(2(v-2))=0

We multiply parentheses

8v+4v-(2(v-2))+6+5=0


We calculate terms in parentheses: -(2(v-2)), so:

2(v-2)

We multiply parentheses

2v-4

Back to the equation:

-(2v-4)


We add all the numbers together, and all the variables

12v-(2v-4)+11=0

We get rid of parentheses

12v-2v+4+11=0

We add all the numbers together, and all the variables

10v+15=0

We move all terms containing v to the left, all other terms to the right

10v=-15

v=-15/10

v=-1+1/2