4x-1/3(x-1)-1/4(3x+2)=2+1/2(7x-2)

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Solution for 4x-1/3(x-1)-1/4(3x+2)=2+1/2(7x-2) equation: 



4x-1/3(x-1)-1/4(3x+2)=2+1/2(7x-2)

We move all terms to the left:

4x-1/3(x-1)-1/4(3x+2)-(2+1/2(7x-2))=0



Domain of the equation: 3(x-1)!=0

x∈R





Domain of the equation: 4(3x+2)!=0

x∈R





Domain of the equation: 2(7x-2))!=0

x∈R



We calculate fractions


(-8x^23/(3(x-1)*4(3x+2)*2(7x-2)))+(-6x^2x/(3(x-1)*4(3x+2)*2(7x-2)))+(-12x^2x/(3(x-1)*4(3x+2)*2(7x-2)))+4x=0



We calculate terms in parentheses: +(-8x^23/(3(x-1)*4(3x+2)*2(7x-2))), so:

-8x^23/(3(x-1)*4(3x+2)*2(7x-2))

We do not support expression: x^23

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