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8v+2(2-3v)=2(v+2)
We move all terms to the left:
8v+2(2-3v)-(2(v+2))=0
We add all the numbers together, and all the variables
8v+2(-3v+2)-(2(v+2))=0
We multiply parentheses
8v-6v-(2(v+2))+4=0
We calculate terms in parentheses: -(2(v+2)), so:We add all the numbers together, and all the variables
2(v+2)
We multiply parentheses
2v+4
Back to the equation:
-(2v+4)
2v-(2v+4)+4=0
We get rid of parentheses
2v-2v-4+4=0
We add all the numbers together, and all the variables
=0
v=0/1
v=0
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