8u+6-5(-2u-2)=2(u-1)

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Solution for 8u+6-5(-2u-2)=2(u-1) equation: 



8u+6-5(-2u-2)=2(u-1)

We move all terms to the left:

8u+6-5(-2u-2)-(2(u-1))=0

We multiply parentheses

8u+10u-(2(u-1))+10+6=0



We calculate terms in parentheses: -(2(u-1)), so:

2(u-1)

We multiply parentheses

2u-2

Back to the equation:

-(2u-2)



We add all the numbers together, and all the variables

18u-(2u-2)+16=0

We get rid of parentheses

18u-2u+2+16=0

We add all the numbers together, and all the variables

16u+18=0

We move all terms containing u to the left, all other terms to the right

16u=-18

u=-18/16

u=-1+1/8

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