110-(15x2)=3x+x

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Solution for 110-(15x2)=3x+x equation:



110-(15x^2)=3x+x
We move all terms to the left:
110-(15x^2)-(3x+x)=0
We add all the numbers together, and all the variables
-15x^2-(+4x)+110=0
We get rid of parentheses
-15x^2-4x+110=0
a = -15; b = -4; c = +110;
Δ = b2-4ac
Δ = -42-4·(-15)·110
Δ = 6616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{6616}=\sqrt{4*1654}=\sqrt{4}*\sqrt{1654}=2\sqrt{1654}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-2\sqrt{1654}}{2*-15}=\frac{4-2\sqrt{1654}}{-30} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+2\sqrt{1654}}{2*-15}=\frac{4+2\sqrt{1654}}{-30} $

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