8u+2-2(-4u-2)=2(u-3)

Solution for 8u+2-2(-4u-2)=2(u-3) equation:

8u+2-2(-4u-2)=2(u-3)

We move all terms to the left:

8u+2-2(-4u-2)-(2(u-3))=0

We multiply parentheses

8u+8u-(2(u-3))+4+2=0


We calculate terms in parentheses: -(2(u-3)), so:

2(u-3)

We multiply parentheses

2u-6

Back to the equation:

-(2u-6)


We add all the numbers together, and all the variables

16u-(2u-6)+6=0

We get rid of parentheses

16u-2u+6+6=0

We add all the numbers together, and all the variables

14u+12=0

We move all terms containing u to the left, all other terms to the right

14u=-12

u=-12/14

u=-6/7