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6x-4+2(2x+1)=-2(x+3)
We move all terms to the left:
6x-4+2(2x+1)-(-2(x+3))=0
We multiply parentheses
6x+4x-(-2(x+3))+2-4=0
We calculate terms in parentheses: -(-2(x+3)), so:We add all the numbers together, and all the variables
-2(x+3)
We multiply parentheses
-2x-6
Back to the equation:
-(-2x-6)
10x-(-2x-6)-2=0
We get rid of parentheses
10x+2x+6-2=0
We add all the numbers together, and all the variables
12x+4=0
We move all terms containing x to the left, all other terms to the right
12x=-4
x=-4/12
x=-1/3
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