-2(8y-4)+2y=8+2(2y-5)

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Solution for -2(8y-4)+2y=8+2(2y-5) equation: 



-2(8y-4)+2y=8+2(2y-5)

We move all terms to the left:

-2(8y-4)+2y-(8+2(2y-5))=0

We add all the numbers together, and all the variables

2y-2(8y-4)-(8+2(2y-5))=0

We multiply parentheses

2y-16y-(8+2(2y-5))+8=0



We calculate terms in parentheses: -(8+2(2y-5)), so:

8+2(2y-5)

determiningTheFunctionDomain
2(2y-5)+8

We multiply parentheses

4y-10+8

We add all the numbers together, and all the variables

4y-2

Back to the equation:

-(4y-2)



We add all the numbers together, and all the variables

-14y-(4y-2)+8=0

We get rid of parentheses

-14y-4y+2+8=0

We add all the numbers together, and all the variables

-18y+10=0

We move all terms containing y to the left, all other terms to the right

-18y=-10

y=-10/-18

y=5/9

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