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8n^2-16n+6=0
a = 8; b = -16; c = +6;
Δ = b2-4ac
Δ = -162-4·8·6
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-8}{2*8}=\frac{8}{16} =1/2 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+8}{2*8}=\frac{24}{16} =1+1/2 $
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