k+11+3k=6(k+11)-2(k-1)

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Solution for k+11+3k=6(k+11)-2(k-1) equation: 



k+11+3k=6(k+11)-2(k-1)

We move all terms to the left:

k+11+3k-(6(k+11)-2(k-1))=0

We add all the numbers together, and all the variables

4k-(6(k+11)-2(k-1))+11=0



We calculate terms in parentheses: -(6(k+11)-2(k-1)), so:

6(k+11)-2(k-1)

We multiply parentheses

6k-2k+66+2

We add all the numbers together, and all the variables

4k+68

Back to the equation:

-(4k+68)



We get rid of parentheses

4k-4k-68+11=0

We add all the numbers together, and all the variables

-57!=0

There is no solution for this equation

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