8n2+4=12n

Solution for 8n2+4=12n equation:

8n^2+4=12n

We move all terms to the left:

8n^2+4-(12n)=0

a = 8; b = -12; c = +4;
Δ = b2-4ac
Δ = -122-4·8·4
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-4}{2*8}=\frac{8}{16}
=1/2
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+4}{2*8}=\frac{16}{16}
=1
$