9z-(12+3z)=3(z-4)

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Solution for 9z-(12+3z)=3(z-4) equation: 



9z-(12+3z)=3(z-4)

We move all terms to the left:

9z-(12+3z)-(3(z-4))=0

We add all the numbers together, and all the variables

9z-(3z+12)-(3(z-4))=0

We get rid of parentheses

9z-3z-(3(z-4))-12=0



We calculate terms in parentheses: -(3(z-4)), so:

3(z-4)

We multiply parentheses

3z-12

Back to the equation:

-(3z-12)



We add all the numbers together, and all the variables

6z-(3z-12)-12=0

We get rid of parentheses

6z-3z+12-12=0

We add all the numbers together, and all the variables

3z=0

z=0/3

z=0

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