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8n(6n+7)=7
We move all terms to the left:
8n(6n+7)-(7)=0
We multiply parentheses
48n^2+56n-7=0
a = 48; b = 56; c = -7;
Δ = b2-4ac
Δ = 562-4·48·(-7)
Δ = 4480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4480}=\sqrt{64*70}=\sqrt{64}*\sqrt{70}=8\sqrt{70}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-8\sqrt{70}}{2*48}=\frac{-56-8\sqrt{70}}{96} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+8\sqrt{70}}{2*48}=\frac{-56+8\sqrt{70}}{96} $
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