2s-3(-s+2)=10

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Solution for 2s-3(-s+2)=10 equation: 



2s-3(-s+2)=10

We move all terms to the left:

2s-3(-s+2)-(10)=0

We add all the numbers together, and all the variables

2s-3(-1s+2)-10=0

We multiply parentheses

2s+3s-6-10=0

We add all the numbers together, and all the variables

5s-16=0

We move all terms containing s to the left, all other terms to the right

5s=16

s=16/5

s=3+1/5

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