8m2+20m=12

Solution for 8m2+20m=12 equation:

8m^2+20m=12

We move all terms to the left:

8m^2+20m-(12)=0

a = 8; b = 20; c = -12;
Δ = b2-4ac
Δ = 202-4·8·(-12)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-28}{2*8}=\frac{-48}{16}
=-3
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+28}{2*8}=\frac{8}{16}
=1/2
$