x(x+10)=(x+5)2x=

Solution for x(x+10)=(x+5)2x= equation:

x(x+10)=(x+5)2x=

We move all terms to the left:

x(x+10)-((x+5)2x)=0

We multiply parentheses

x^2+10x-((x+5)2x)=0


We calculate terms in parentheses: -((x+5)2x), so:

(x+5)2x

We multiply parentheses

2x^2+10x

Back to the equation:

-(2x^2+10x)


We get rid of parentheses

x^2-2x^2+10x-10x=0

We add all the numbers together, and all the variables

-1x^2=0

a = -1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-1)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-2}=0$