If it's not what You are looking for type in the equation solver your own equation and let us solve it.
8k-1/3k=5k
We move all terms to the left:
8k-1/3k-(5k)=0
Domain of the equation: 3k!=0We add all the numbers together, and all the variables
k!=0/3
k!=0
k∈R
3k-1/3k=0
We multiply all the terms by the denominator
3k*3k-1=0
Wy multiply elements
9k^2-1=0
a = 9; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·9·(-1)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6}{2*9}=\frac{-6}{18} =-1/3 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6}{2*9}=\frac{6}{18} =1/3 $
| s(11-s)=22 | | 6x-18=6(2x-6) | | 1.20x+1.08=7.80 | | 1/4+1/4n=1/2n | | -2x+2/3=4/3 | | (-3/7)h=6 | | 2(4+3y)=8y-12-12 | | 27=x2+10x-16x | | 13=w/13-4 | | (6x-5)=(x+17) | | −f+2+4f=8−3 | | 6(3y)-y=69 | | (3+2i)(-4-3i)=0 | | 970=m−-682 | | 2(3x-1)^2+13(3x-1)-7=0 | | 2(3x-1)+13(3x-1)-7=0 | | -9=x/3+4 | | -7=-6/c+12 | | 5−2u=1 | | -3+5+6g=11=3g | | 6(x+1)3=5x-2 | | (x-4)(x-5)(x-6)(x-7)=283 | | 709=d−147 | | 1=(13/18)+(y/18) | | 12−3s=6 | | Z=-3a-2 | | x-7=8-6x+36 | | n−707=84 | | 36x^2+8x+1=0 | | 15+c=40 | | q+499=910 | | 4=p+8 |