27=x2+10x-16x

Solution for 27=x2+10x-16x equation:

27=x2+10x-16x

We move all terms to the left:

27-(x2+10x-16x)=0

We add all the numbers together, and all the variables

-(+x^2-6x)+27=0

We get rid of parentheses

-x^2+6x+27=0

We add all the numbers together, and all the variables

-1x^2+6x+27=0

a = -1; b = 6; c = +27;
Δ = b2-4ac
Δ = 62-4·(-1)·27
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-12}{2*-1}=\frac{-18}{-2}
=+9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+12}{2*-1}=\frac{6}{-2}
=-3
$