8i-6+2(5i-3)+4i=20-4i+6

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Solution for 8i-6+2(5i-3)+4i=20-4i+6 equation: 



8i-6+2(5i-3)+4i=20-4i+6

We move all terms to the left:

8i-6+2(5i-3)+4i-(20-4i+6)=0

We add all the numbers together, and all the variables

8i+2(5i-3)+4i-(-4i+26)-6=0

We add all the numbers together, and all the variables

12i+2(5i-3)-(-4i+26)-6=0

We multiply parentheses

12i+10i-(-4i+26)-6-6=0

We get rid of parentheses

12i+10i+4i-26-6-6=0

We add all the numbers together, and all the variables

26i-38=0

We move all terms containing i to the left, all other terms to the right

26i=38

i=38/26

i=1+6/13

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