(4x-1)(3x-1)=118

Solution for (4x-1)(3x-1)=118 equation:

(4x-1)(3x-1)=118

We move all terms to the left:

(4x-1)(3x-1)-(118)=0

We multiply parentheses ..

(+12x^2-4x-3x+1)-118=0

We get rid of parentheses

12x^2-4x-3x+1-118=0

We add all the numbers together, and all the variables

12x^2-7x-117=0

a = 12; b = -7; c = -117;
Δ = b2-4ac
Δ = -72-4·12·(-117)
Δ = 5665
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{5665}}{2*12}=\frac{7-\sqrt{5665}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{5665}}{2*12}=\frac{7+\sqrt{5665}}{24}
$