8c=10-3(-6c-10)

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Solution for 8c=10-3(-6c-10) equation: 



8c=10-3(-6c-10)

We move all terms to the left:

8c-(10-3(-6c-10))=0



We calculate terms in parentheses: -(10-3(-6c-10)), so:

10-3(-6c-10)

determiningTheFunctionDomain
-3(-6c-10)+10

We multiply parentheses

18c+30+10

We add all the numbers together, and all the variables

18c+40

Back to the equation:

-(18c+40)



We get rid of parentheses

8c-18c-40=0

We add all the numbers together, and all the variables

-10c-40=0

We move all terms containing c to the left, all other terms to the right

-10c=40

c=40/-10

c=-4

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