-108=6(v-8)+6v

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Solution for -108=6(v-8)+6v equation:



-108=6(v-8)+6v
We move all terms to the left:
-108-(6(v-8)+6v)=0
We calculate terms in parentheses: -(6(v-8)+6v), so:
6(v-8)+6v
We add all the numbers together, and all the variables
6v+6(v-8)
We multiply parentheses
6v+6v-48
We add all the numbers together, and all the variables
12v-48
Back to the equation:
-(12v-48)
We get rid of parentheses
-12v+48-108=0
We add all the numbers together, and all the variables
-12v-60=0
We move all terms containing v to the left, all other terms to the right
-12v=60
v=60/-12
v=-5

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