8b-(3b+4)b=11

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Solution for 8b-(3b+4)b=11 equation: 



8b-(3b+4)b=11

We move all terms to the left:

8b-(3b+4)b-(11)=0

We multiply parentheses

-3b^2+8b-4b-11=0

We add all the numbers together, and all the variables

-3b^2+4b-11=0

a = -3; b = 4; c = -11;
Δ = b2-4ac
Δ = 42-4·(-3)·(-11)
Δ = -116
Delta is less than zero, so there is no solution for the equation

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