8b+2+5b=-6(8+3b)+3(b-2)

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Solution for 8b+2+5b=-6(8+3b)+3(b-2) equation: 



8b+2+5b=-6(8+3b)+3(b-2)

We move all terms to the left:

8b+2+5b-(-6(8+3b)+3(b-2))=0

We add all the numbers together, and all the variables

8b+5b-(-6(3b+8)+3(b-2))+2=0

We add all the numbers together, and all the variables

13b-(-6(3b+8)+3(b-2))+2=0



We calculate terms in parentheses: -(-6(3b+8)+3(b-2)), so:

-6(3b+8)+3(b-2)

We multiply parentheses

-18b+3b-48-6

We add all the numbers together, and all the variables

-15b-54

Back to the equation:

-(-15b-54)



We get rid of parentheses

13b+15b+54+2=0

We add all the numbers together, and all the variables

28b+56=0

We move all terms containing b to the left, all other terms to the right

28b=-56

b=-56/28

b=-2

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