-5(1+2v)-6(2+3v)=11

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Solution for -5(1+2v)-6(2+3v)=11 equation: 



-5(1+2v)-6(2+3v)=11

We move all terms to the left:

-5(1+2v)-6(2+3v)-(11)=0

We add all the numbers together, and all the variables

-5(2v+1)-6(3v+2)-11=0

We multiply parentheses

-10v-18v-5-12-11=0

We add all the numbers together, and all the variables

-28v-28=0

We move all terms containing v to the left, all other terms to the right

-28v=28

v=28/-28

v=-1

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