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8a-24/4a-12=0
Domain of the equation: 4a!=0We multiply all the terms by the denominator
a!=0/4
a!=0
a∈R
8a*4a-12*4a-24=0
Wy multiply elements
32a^2-48a-24=0
a = 32; b = -48; c = -24;
Δ = b2-4ac
Δ = -482-4·32·(-24)
Δ = 5376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5376}=\sqrt{256*21}=\sqrt{256}*\sqrt{21}=16\sqrt{21}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-16\sqrt{21}}{2*32}=\frac{48-16\sqrt{21}}{64} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+16\sqrt{21}}{2*32}=\frac{48+16\sqrt{21}}{64} $
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