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3(2r+1)-5=9(r-1)-3r
We move all terms to the left:
3(2r+1)-5-(9(r-1)-3r)=0
We multiply parentheses
6r-(9(r-1)-3r)+3-5=0
We calculate terms in parentheses: -(9(r-1)-3r), so:We add all the numbers together, and all the variables
9(r-1)-3r
We add all the numbers together, and all the variables
-3r+9(r-1)
We multiply parentheses
-3r+9r-9
We add all the numbers together, and all the variables
6r-9
Back to the equation:
-(6r-9)
6r-(6r-9)-2=0
We get rid of parentheses
6r-6r+9-2=0
We add all the numbers together, and all the variables
7!=0
There is no solution for this equation
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