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8a-(5-4a)=6-(4a+9)
We move all terms to the left:
8a-(5-4a)-(6-(4a+9))=0
We add all the numbers together, and all the variables
8a-(-4a+5)-(6-(4a+9))=0
We get rid of parentheses
8a+4a-(6-(4a+9))-5=0
We calculate terms in parentheses: -(6-(4a+9)), so:We add all the numbers together, and all the variables
6-(4a+9)
determiningTheFunctionDomain -(4a+9)+6
We get rid of parentheses
-4a-9+6
We add all the numbers together, and all the variables
-4a-3
Back to the equation:
-(-4a-3)
12a-(-4a-3)-5=0
We get rid of parentheses
12a+4a+3-5=0
We add all the numbers together, and all the variables
16a-2=0
We move all terms containing a to the left, all other terms to the right
16a=2
a=2/16
a=1/8
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