8/x=1/4x+1

Solution for 8/x=1/4x+1 equation:

8/x=1/4x+1

We move all terms to the left:

8/x-(1/4x+1)=0


Domain of the equation: x!=0

x∈R



Domain of the equation: 4x+1)!=0

x∈R


We get rid of parentheses

8/x-1/4x-1=0

We calculate fractions


32x/4x^2+(-x)/4x^2-1=0

We add all the numbers together, and all the variables

32x/4x^2+(-1x)/4x^2-1=0

We multiply all the terms by the denominator


32x+(-1x)-1*4x^2=0

Wy multiply elements

-4x^2+32x+(-1x)=0

We get rid of parentheses

-4x^2+32x-1x=0

We add all the numbers together, and all the variables

-4x^2+31x=0

a = -4; b = 31; c = 0;
Δ = b2-4ac
Δ = 312-4·(-4)·0
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-31}{2*-4}=\frac{-62}{-8}
=7+3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+31}{2*-4}=\frac{0}{-8}
=0
$