43=7+3(5+2u)

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Solution for 43=7+3(5+2u) equation: 



43=7+3(5+2u)

We move all terms to the left:

43-(7+3(5+2u))=0

We add all the numbers together, and all the variables

-(7+3(2u+5))+43=0



We calculate terms in parentheses: -(7+3(2u+5)), so:

7+3(2u+5)

determiningTheFunctionDomain
3(2u+5)+7

We multiply parentheses

6u+15+7

We add all the numbers together, and all the variables

6u+22

Back to the equation:

-(6u+22)



We get rid of parentheses

-6u-22+43=0

We add all the numbers together, and all the variables

-6u+21=0

We move all terms containing u to the left, all other terms to the right

-6u=-21

u=-21/-6

u=3+1/2

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