8/9(3i+27)=2/7i+68

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Solution for 8/9(3i+27)=2/7i+68 equation: 



8/9(3i+27)=2/7i+68

We move all terms to the left:

8/9(3i+27)-(2/7i+68)=0



Domain of the equation: 9(3i+27)!=0

i∈R





Domain of the equation: 7i+68)!=0

i∈R



We get rid of parentheses

8/9(3i+27)-2/7i-68=0

We calculate fractions


56i/(189i^2+1701i)+(-18i3/(189i^2+1701i)-68=0

We calculate fractions

We do not support eipression: i^3

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